1036 Boys vs Girls (25 point(s))

最新推荐文章于 2020-12-13 19:32:41 发布

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本文介绍了一个简单的算法，用于分析学生数据集中的性别成绩差异。通过读取输入文件，该算法将学生分为男性和女性两组，并找出每组中成绩最高和最低的学生。最后，它计算并输出女性最高成绩与男性最低成绩之间的差距。

1036 Boys vs Girls (25 point(s))

This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student's name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and gradeis an integer between 0 and 100. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference gradeF−gradeM. If one such kind of student is missing, output Absent in the corresponding line, and output NA in the third line instead.

Sample Input 1:

3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95

Sample Output 1:

Mary EE990830
Joe Math990112
6

Sample Input 2:

1
Jean M AA980920 60

Sample Output 2:

Absent
Jean AA980920
NA

简单排序题。

#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;
int flag;
struct student{
	string name,id;int grade;
	student(string n,string i,int g):name(n),id(i),grade(g){}
	bool operator < (const student &other) const{
		if(flag==1) return grade<other.grade;
		else if(flag==2) return  grade>other.grade;
	}
};
vector<student> boys;
vector<student> girls;
int main(void){
	int n;cin>>n;
	string name,gender,id;int grade;
	while(n--){
		cin>>name>>gender>>id>>grade;
		if(gender=="M") boys.push_back(student(name,id,grade));
		if(gender=="F") girls.push_back(student(name,id,grade));
	}
	flag = 1;sort(boys.begin(),boys.end());
	flag = 2;sort(girls.begin(),girls.end());
	
	if(girls.size()==0) cout<<"Absent"<<endl;
	else  cout<< girls[0].name<<" "<<girls[0].id<<endl;
	
	if(boys.size()==0) cout<<"Absent"<<endl;
	else cout<< boys[0].name<<" "<<boys[0].id<<endl; 
	 
	if(boys.size()==0||girls.size()==0) cout<<"NA"<<endl;
	else cout<<girls[0].grade-boys[0].grade<<endl;
	return 0;
}