| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 6429 | Accepted: 2500 |
Description
Here, n is 8, m is 10, blank squares represent the integer 0, raised squares represent unplayed positions, and the figures resembling asterisks represent mines. The leftmost image represents the partially played game. From the first image to the second, the player has played two moves, each time choosing a safe grid position. From the second image to the third, the player is not so lucky; he chooses a position with a mine and therefore loses. The player wins if he continues to make safe moves until only m unplayed positions remain; these must necessarily contain the mines.
Your job is to read the information for a partially played game and to print the corresponding board.
Input
Output
Sample Input
8 ...**..* ......*. ....*... ........ ........ .....*.. ...**.*. .....*.. xxx..... xxxx.... xxxx.... xxxxx... xxxxx... xxxxx... xxx..... xxxxx...
Sample Output
001..... 0013.... 0001.... 00011... 00001... 00123... 001..... 00123...
注意:如果踩到地雷,要把所有地雷表示出来;
#include <iostream>
using namespace std;
#define MAX 12
int n;
char map[MAX][MAX],ans[MAX][MAX];
int count(int i,int j,int n){
int ans=0;
if (map[i-1][j-1]=='*' && i-1>=0 && j-1>=0)
ans++;
if (map[i-1][j]=='*' && i-1>=0)
ans++;
if (map[i-1][j+1]=='*' && i-1>=0 && j+1<n)
ans++;
if (map[i][j-1]=='*' && j-1>=0)
ans++;
if (map[i][j]=='*')
ans++;
if (map[i][j+1]=='*' && j+1<n)
ans++;
if (map[i+1][j-1]=='*' && i+1<n && j-1>=0)
ans++;
if (map[i+1][j]=='*' && i+1<n)
ans++;
if (map[i+1][j+1]=='*' && i+1<n && j+1<n)
ans++;
return ans;
}
int main(){
while (cin>>n){
for (int i=0;i<n;i++)
for (int j=0;j<n;j++)
cin>>map[i][j];
int flag=0;
for (int i=0;i<n;i++){
for (int j=0;j<n;j++){
cin>>ans[i][j];
if (map[i][j]=='*' && ans[i][j]=='x')
flag=1;
if (ans[i][j]=='x'){
int k=count(i,j,n);
ans[i][j]=k+'0';
}
}
}
for (int i=0;i<n;i++){
for (int j=0;j<n;j++){
if (flag==1 && map[i][j]=='*')
cout<<map[i][j];
else
cout<<ans[i][j];
}
cout<<endl;
}
}
return 0;
}
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