问题描述
给定当前的时间,请用英文的读法将它读出来。
时间用时h和分m表示,在英文的读法中,读一个时间的方法是:
如果m为0,则将时读出来,然后加上“o'clock”,如3:00读作“three o'clock”。
如果m不为0,则将时读出来,然后将分读出来,如5:30读作“five thirty”。
时和分的读法使用的是英文数字的读法,其中0~20读作:
0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。
30读作thirty,40读作forty,50读作fifty。
对于大于20小于60的数字,首先读整十的数,然后再加上个位数。如31首先读30再加1的读法,读作“thirty one”。
按上面的规则21:54读作“twenty one fifty four”,9:07读作“nine seven”,0:15读作“zero fifteen”。
输入格式
输入包含两个非负整数h和m,表示时间的时和分。非零的数字前没有前导0。h小于24,m小于60。
输出格式
输出时间时刻的英文。
样例输入
0 15
样例输出
zero fifteen
import java.util.Scanner;
public class Main {
public static int h = 0;
public static int m = 0;
public static void main(String[] args) {
String[] s = {"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen"
,"fifteen","sixteen","seventeen","eighteen","nineteen","twenty","twenty one","twenty two","twenty three"};
Scanner sc = new Scanner(System.in);
h = sc.nextInt();
m = sc.nextInt();
String result = "";
for(int i = 0 ; i<24;i++ ){
if(i==h){
result +=s[i]+" ";
break;
}
}
if(m == 0){
result += "o'clock";
}
for(int i = 1 ; i<=20;i++ ){
if(i==m){
result +=s[i];
break;
}
}
if(m>50){
result+="fifty "+s[m-50];
}else if(m >40){
if(m== 50){
result += "fifty";
}else
result += "forty "+s[m-40];
}else if(m>30){
if(m==40)
result +="forty";
else
result += "thirty "+s[m-30];
}else if(m>20){
if(m == 30)
result +="thirty";
else
result += "twenty "+s[m-20];
}
System.out.println(result);
}
}