mysql判断时间是否是当天，昨天。。。

今天  
select * from 表名 where to_days(时间字段名) = to_days(now());  
昨天  
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1  
7天  
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)  
近30天  
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)  
本月  
SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )  
上一月  
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1  
#查询本季度数据  
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());  
#查询上季度数据  
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));  
#查询本年数据  
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());  
#查询上年数据  
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));  
查询当前这周的数据   
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());  
查询上周的数据  
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;  
查询当前月份的数据  
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')  
查询距离当前现在6个月的数据  
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();  
查询上个月的数据  
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')  
select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;  
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())  
select *   
from user
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())  
select *   
from [ user ]   
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())  
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())  
select *   
from [ user ]   
where pudate between 上月最后一天  
and 下月第一天  
where date(regdate)   =   curdate();  
select   *   from   test   where year(regdate)=year(now())   and month(regdate)=month(now())   and day(regdate)=day(now())  
SELECT date( c_instime ) ,curdate( )  
FROM `t_score`  
WHERE 1  
LIMIT 0 , 30