博客介绍了LeetCode 129题目的解决方案，即如何实现图的深拷贝。讨论了深拷贝与浅拷贝的概念，并提供了C++的BFS和DFS实现。通过一个图示例说明了图的结构，重点在于利用广度优先搜索或深度优先搜索避免拷贝过程中的循环引用问题。
题目：
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use# as a separator for each node, and
, as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {
0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
- First node is labeled as
0. Connect node0to both nodes1and2. - Second node is labeled as
1. Connect node1to node2. - Third node is labeled as
2. Connect node
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