Next Mayor Aizu - 1159

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本文介绍了一个独特的市长选举游戏，通过模拟n位候选人轮流从碗中取球的过程来决定胜者。游戏采用特定规则，最终拥有所有球的候选人将当选为下一任市长。文章提供了完整的实现代码。

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Next Mayor

Aizu - 1159

Problem A:

One of the oddest traditions of the town of Gameston may be that even the town mayor of the next term is chosen according to the result of a game. When the expiration of the term of the mayor approaches, at least three candidates, including the mayor of the time, play a game of pebbles, and the winner will be the next mayor.

The rule of the game of pebbles is as follows. In what follows, n is the number of participating candidates.

Requisites

A round table, a bowl, and plenty of pebbles.

Start of the Game

A number of pebbles are put into the bowl; the number is decided by the Administration Commission using some secret stochastic process. All the candidates, numbered from 0 to n-1 sit around the round table, in a counterclockwise order. Initially, the bowl is handed to the serving mayor at the time, who is numbered 0.

Game Steps

When a candidate is handed the bowl and if any pebbles are in it, one pebble is taken out of the bowl and is kept, together with those already at hand, if any. If no pebbles are left in the bowl, the candidate puts all the kept pebbles, if any, into the bowl. Then, in either case, the bowl is handed to the next candidate to the right. This step is repeated until the winner is decided.

End of the Game

When a candidate takes the last pebble in the bowl, and no other candidates keep any pebbles, the game ends and that candidate with all the pebbles is the winner.

A math teacher of Gameston High, through his analysis, concluded that this game will always end within a finite number of steps, although the number of required steps can be very large.

Input

The input is a sequence of datasets. Each dataset is a line containing two integers n and p separated by a single space. The integer n is the number of the candidates including the current mayor, and the integer p is the total number of the pebbles initially put in the bowl. You may assume 3 ≤ n ≤ 50 and 2 ≤ p ≤ 50.

With the settings given in the input datasets, the game will end within 1000000 (one million) steps.

The end of the input is indicated by a line containing two zeros separated by a single space.

Output

The output should be composed of lines corresponding to input datasets in the same order, each line of which containing the candidate number of the winner. No other characters should appear in the output.

Sample Input

Output for the Sample Input

题目大意：现在要选市长，有n个人竞选市长，碗里有p个球，从编号为0位置开始，如果碗里有球就拿一个，如果没有就把手中有的所有球放进碗里，直到全部的球到一个人手上，这个人为市长游戏结束。

思路：直接暴力模拟

代码：

#include<stdio.h>
int main()
{
    int n,p;
    while(~scanf("%d%d",&n,&p)&&(n+p))
    {
        int a[150]={0},ans,flag=0,ball=p;
        while(1)
        {
            for(int i=0;i<n;i++)
            {
                if(ball)
                    a[i]++,ball--;
                else
                    ball+=a[i],a[i]=0;
                if(a[i]==p)
                {
                    ans=i;
                    flag=1;
                    break;
                }
            }
            if(flag)
                break;
        }
        printf("%d\n",ans);
    }
    return 0;
}