Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
/** * Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
下边的这个是递归
出处:http://www.bubuko.com/infodetail-954959.html
public class Solution {public boolean isSameTree(TreeNode p, TreeNode q) {
if(p==null&&q==null) return true;
if(p==null||q==null) return false;
if(p.val!=q.val) return false;
return isSameTree(p.left, q.left)&&isSameTree(p.right, q.right);
}
}
下边的这个是迭代
出处:http://blog.youkuaiyun.com/xudli/article/details/8557010
public class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
Queue<TreeNode> q1 = new LinkedList<TreeNode>();
Queue<TreeNode> q2 = new LinkedList<TreeNode>();
q1.offer(p);
q2.offer(q);
while( !q1.isEmpty() && !q2.isEmpty() ) {
TreeNode x = q1.poll();
TreeNode y = q2.poll();
if(x==null) {
if( y!=null) return false;
else continue;
}
if(y==null || x.val!=y.val) return false;
q1.offer( x.left);
q1.offer( x.right);
q2.offer(y.left);
q2.offer(y.right);
}
return true;
}
}