python send alarm_info

最新推荐文章于 2024-03-24 11:23:29 发布

原创最新推荐文章于 2024-03-24 11:23:29 发布 · 340 阅读

0 ·

CC 4.0 BY-SA版权

python 专栏收录该内容

11 篇文章

订阅专栏

本文介绍了一个使用Python进行数据库操作并发送HTTP请求的例子。该程序通过pymysql库连接数据库，读取alarm表中的数据，并使用requests库向本地服务器发送POST请求。文章展示了如何构建动态URL参数及处理响应。

#!/usr/bin/python3

import pymysql
import requests


# 访问请求的方法
def requestUrl(result):
    id = str(result['id'])
    entName = str(result['entName'])
    warnType = str(result['warnType'])
    headers = {'Content-Type': 'application/json'}
    #datas = json.dumps({"id":"202009151111","entName": "织里安木童衣有限公司","entChartered": "","warnType": "2","supervisorName": "韦云飞","phoneNumber": "18868213106","address": "","warnInfo":"测试","areaStreet": "","areaCountry": "","occurTime": "2020-09-15 15:26:55"})
    param="id="+id+"&entName="+entName+"&entChartered&warnType="+warnType+"&supervisorName=韦云飞&phoneNumber=119&address&warnInfo=电流过大&areaStreet&areaCountry&occurTime=2020-07-28 20:30:21"
    url="http://localhost:8080/park/insert?"+param
    r = requests.post(url,headers=headers)
    print(r.text)



#主函数用法
if __name__ == '__main__':
    # 打开数据库连接
    db = pymysql.connect("xxx.xx.xxx.xxx", "xxx", "xxx+", "xxx")
    # 使用cursor()方法获取操作游标
    cursor = db.cursor(cursor = pymysql.cursors.DictCursor)
    # SQL 查询语句
    sql = "SELECT * FROM alarm "
    try:
        # 执行SQL语句
        cursor.execute(sql)
        # 获取所有记录列表
        results = cursor.fetchall()
        for result in results:
            requestUrl(result)
            id = result[0]
            entName = result[1]
            # 打印结果
            print("id=%s,entName=%s" % \
              (id, entName))
        total = cursor.rowcount
        print("总数: %s" % \
              (total))
        print("处理完成")
    except Exception as e:
        print(e)
        print("Error: unable to fetch data")
    # 关闭数据库连接
    db.close()