【SICP练习】151 练习4.7

本文深入解析了let*表达式的工作原理,它如何按顺序绑定变量,并在环境中可见。通过实例展示了let*如何重写为嵌套的let表达式,并提供了将let*转换为嵌套let的实现代码。探讨了在已实现let的基础上,是否只需添加新子句即可处理let*,还是必须显式展开。

练习4-7

原文

Exercise 4.7. Let* is similar to let, except that the bindings of the let variables are performed sequentially from left to right, and each binding is made in an environment in which all of the preceding bindings are visible. For example

(let* ((x 3) (y (+ x 2)) (z (+ x y 5))) (* x z))

returns 39. Explain how a let* expression can be rewritten as a set of nested let expressions, and write a procedure let*->nested-lets that performs this transformation. If we have already implemented let (exercise 4.6) and we want to extend the evaluator to handle let*, is it sufficient to add a clause to eval whose action is

(eval (let*->nested-lets exp) env)

or must we explicitly expand let* in terms of non-derived expressions?

分析

这道题和上一道很类似,抓住题中的要点就会迎刃而解啦。那就是说从左至右求值,那么我们可以用list和car以及cdr来完成,核心思想是用递归,不断的向右边推进,直到exp为空,此时就返回body,然后结束构造。至于tagged-list?这些和上一题都是一样的。

代码


(define (let*? expr) (tagged-list? expr 'let*))

(define (let*-body expr) (caddr expr))

(define (let*-exp expr) (cadr expr))

(define (let*->nested-lets expr) (let ((exp (let*-exp expr)) (body (let*-body expr))) (defien (make-lets exprs) (if (null? exprs) body (list 'let (list (car exprs)) (make-lets (cdr exprs))))) (make-lets exp)))



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转载于:https://my.oschina.net/nomasp/blog/503387

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