【解题思路】
暴力法,超出时间限制。
class Solution {
public int[] maxSlidingWindow(int[] nums, int k) {
int n = nums.length - k + 1;
int[] ans = new int[n];
int max = -99999;
for(int i = 0; i < k; i++)
{
if(nums[i] > max)
{
max = nums[i];
}
}
ans[0] = max;
for(int i = k; i < nums.length; i++)
{
if(nums[i] > ans[i-k])
{
ans[i-k+1] = nums[i];
}
else if(ans[i-k] != nums[i-k])
{
ans[i-k+1] = ans[i-k];
}
else{
max = -99999;
for(int j = i; j > i-k; j--)
{
if(nums[j] > max)
{
max = nums[j];
}
}
ans[i-k+1] = max;
}
}
return ans;
}
}
class Solution {
public int[] maxSlidingWindow(int[] nums, int k) {
int n = nums.length;
PriorityQueue<int[]> pq = new PriorityQueue<int[]>(new Comparator<int[]>() {
public int compare(int[] pair1, int[] pair2) {
return pair1[0] != pair2[0] ? pair2[0] - pair1[0] : pair2[1] - pair1[1];
}
});
for (int i = 0; i < k; ++i) {
pq.offer(new int[]{nums[i], i});
}
int[] ans = new int[n - k + 1];
ans[0] = pq.peek()[0];
for (int i = k; i < n; ++i) {
pq.offer(new int[]{nums[i], i});
while (pq.peek()[1] <= i - k) {
pq.poll();
}
ans[i - k + 1] = pq.peek()[0];
}
return ans;
}
}