南邮 OJ 1125 Substring

本博客探讨如何从给定的子字符串集合中构造出字典序最小的原始字符串。

Substring

时间限制(普通/Java) : 2000 MS/ 6000 MS          运行内存限制 : 65536 KByte
总提交 : 201            测试通过 : 49 

比赛描述

Dr lee cuts a string S into N pieces , s[1],……,s[N].
Now , Dr lee gives you these N sub-string:s[1]…,s[N].T there might be several possibilities that the string S could be . For example , if Dr.lee gives you three sub-strings{“a”,”ab”,”ac”},the string S could be “aabac”,”aacab”,”abaac”,…
Your task is to output the lexicographically smallest S.

输入

The first line of the input is a positive integer T.T is the number of the test cases followed.
The first line of each test case is a positive integer N(1<=N<=8) which represents the number of sub-strings.After that,N lines followed. The i-th line is the i-th sub-string s[i].Assume that the length of each sub-string is positive and less than 100.

输出

The output of each test is the lexicographically smallest S.No redundant spaces are needed.

样例输入

1
3
a
ab
ac

样例输出

aabac

题目来源

第九届中山大学程序设计竞赛预选题




#include<iostream>
#include<string>
#include<vector>
#include<algorithm>
using namespace std;

int main(){
	int T,N,i;
	string s,min_s,ss[8];
	vector<string>::iterator it;
	cin>>T;
	while(T--){
		cin>>N;
		min_s = "~";
		for(i=0;i<N;++i){
			cin>>ss[i];
		}
		sort(ss,ss+N);
		do{
			s = ss[0];
			for(i=1;i<N;++i){
				s += ss[i];
			}
			if(min_s>s){
				min_s = s;
			}
		}while(next_permutation(ss,ss+N));
		cout<<min_s<<endl;
	}
}






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