如何在tomcat启动时自动加载一个类

最新推荐文章于 2021-04-27 21:10:19 发布

CC勇哥

最新推荐文章于 2021-04-27 21:10:19 发布

阅读量1k

点赞数

分类专栏： IT技术文章标签： tomcat thread myeclipse encoding class

IT技术专栏收录该内容

2 篇文章

订阅专栏

本文介绍如何在Myeclipse中配置web.xml，使Tomcat能在启动时自动加载指定的Servlet（InitServlet），并展示了InitServlet的具体实现，该Servlet用于启动两个线程。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

我在Myeclipse工程里的web.xml文件添加一个tomcat启动时自动加载类的设置：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.4" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<servlet>
<servlet-name>InitServlet</servlet-name>
<servlet-class>com.synfuels.window.util.InitServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>InitServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>

InitServlet是一个启动线程的类：

package com.synfuels.window.util;

import java.io.IOException;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class InitServlet extends HttpServlet {

/**
*
*/
private static final long serialVersionUID = 1L;

private DataServer ds = DataServer.getInstance();

public InitServlet(){

}

public void init() throws ServletException {
Thread producerThread = new Thread(new Producer(ds));
Thread connSocketThread = new Thread(new ConnSocket(ds));
producerThread.start();
connSocketThread.start();
}

public void doGet(HttpServletRequest httpservletrequest,
HttpServletResponse httpservletresponse) throws ServletException,
IOException {
}

public void destory() {

}

}