java.sql.SQLSyntaxErrorException: ORA-02049: 超时: 分布式事务处理等待锁处理

应用发版后部分服务器重启导致应用服务器启动时出现ORA-02049错误,提示超时等待分布式事务处理锁。此问题通常由并发操作引起,建议等待分布式_lock_timeout秒后再尝试,一般情况下会自动恢复。

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 **** Error      星期四 十月 25 01:23:36 CST 2012        1351099416103   /atg/dynamo/messaging/SqlJmsProvider    ---     java.sql.SQLSyntaxErrorException: ORA-02049: 超时: 分布式事务处理等待锁
**** Error      星期四 十月 25 01:23:36 CST 2012        1351099416103   /atg/dynamo/messaging/SqlJmsProvider

**** Error      星期四 十月 25 01:23:36 CST 2012        1351099416103   /atg/dynamo/messaging/SqlJmsProvider          

.....


应用发版部分服务器重启,应用服务器启动报错“超时: 分布式事务处理等待锁”,根据ORACLE官方的说法这是避免死锁的一种机制

遇到这种问题时等一会(至少等distributed_lock_timeout那么久吧,所以这个值设置过大会导致一些不可知的风险),再次尝试会自动恢复。



Error:  ORA 2049
Text:   timeout: distributed transaction waiting for lock
-------------------------------------------------------------------------------
Cause:  Exceeded <Parameter:DISTRIBUTED_LOCK_TIMEOUT> seconds waiting for lock.
Action: treat as a deadlock
 

*** Important: The notes below are for experienced users - See Note:22080.1

Explanation:
	Ignore the "Action" above - this is non-sense.

	Basically ORA 2049 is signalled if:

        a) you are waiting on another sessions TX enqueue
           (Eg: usually you are waiting for a row lock)

   AND  b) you are performing a distributed operation.
           Eg: You are using a DB link for something, even if it is only a
                select

   AND  c) You wait for longer than 'distributed_lock_timeout'

    The use of a DB Link opens you up to distributed rules of operation 
    even if you only READ from it.
 
    You can either increase the timeout OR handle the ORA 2049 as a 'try again' 
    exception that is not fatal. This mechanism exists to prevent deadlock 
    so any handling of 'TRY AGAIN' should include an escape clause to prevent 
    deadlock. 


Example:
    Session 1                                Session 2
    ~~~~~~~~~				     ~~~~~~~~~
    update t2@LINK set b=4 where b=3;                                          
                                             select * from dual@LINK;          
                                             update t2 set b=4 where b=3;      
                                             ^^ ORA 2049                       
  OR EVEN 
    update t2 set b=4 where b=3;                                               
                                             select * from dual@LINK;          
                                             update t2 set b=4 where b=3;      
                                             ^^ ORA 2049


java.sql.SQLSyntaxErrorException: ORA-00933: SQL 命令未正确结束 是一个常见的SQL语法错误,通常发生在使用JDBC连接Oracle数据库时。这个错误的具体含义是SQL语句的语法不正确,导致命令无法正常结束。以下是一些可能的原因和解决方法: ### 可能的原因 1. **SQL语句末尾有多余的分号**:在JDBC中执行SQL语句时,语句末尾不需要加分号。 2. **使用了不支持的SQL语法**:某些SQL语法在JDBC中可能不被支持。 3. **SQL语句中存在拼写错误或语法错误**。 4. **使用了不正确的占位符**:在预编译语句(PreparedStatement)中使用了不正确的占位符。 ### 解决方法 1. **检查SQL语句末尾是否有多余的分号**: ```java String sql = "SELECT * FROM users"; // 正确 // String sql = "SELECT * FROM users;"; // 错误 ``` 2. **确保SQL语法正确**: ```java String sql = "SELECT * FROM users WHERE id = ?"; // 正确 ``` 3. **使用预编译语句(PreparedStatement)时,确保占位符使用正确**: ```java String sql = "SELECT * FROM users WHERE id = ?"; PreparedStatement pstmt = connection.prepareStatement(sql); pstmt.setInt(1, userId); ResultSet rs = pstmt.executeQuery(); ``` 4. **检查SQL语句中是否有拼写错误或语法错误**。 ### 示例代码 ```java import java.sql.Connection; import java.sql.DriverManager; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; public class OracleJDBCExample { public static void main(String[] args) { String url = "jdbc:oracle:thin:@localhost:1521:xe"; String user = "username"; String password = "password"; String sql = "SELECT * FROM users WHERE id = ?"; try (Connection connection = DriverManager.getConnection(url, user, password); PreparedStatement pstmt = connection.prepareStatement(sql)) { pstmt.setInt(1, 1); ResultSet rs = pstmt.executeQuery(); while (rs.next()) { System.out.println("ID: " + rs.getInt("id")); System.out.println("Name: " + rs.getString("name")); } } catch (SQLException e) { e.printStackTrace(); } } } ``` ###
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