Previous Permutation 上一个排列
Description
Given a list of integers, which denote a permutation.
Find the previous permutation in ascending order.
public class Solution {
/*
* @param nums: A list of integers
* @return: A list of integers that's previous permuation
*/
public List<Integer> previousPermuation(List<Integer> nums) {
// write your code here
int pre = nums.size()-1;
while (pre > 0 && nums.get(pre-1) <= nums.get(pre)) pre--;
pre--;
if (pre >= 0) {
int cur = pre+1;
while (cur < nums.size() && nums.get(cur) < nums.get(pre)) cur++;
cur--;
int temp = nums.get(cur);
nums.set(cur, nums.get(pre));
nums.set(pre, temp);
}
int left = pre+1;
int right = nums.size()-1;
while (left < right) {
int temp = nums.get(left);
nums.set(left, nums.get(right));
nums.set(right, temp);
left++;
right--;
}
return nums;
}
}
该博客介绍了一种算法,用于找到给定升序排列列表的前一个排列。通过迭代和交换元素,算法有效地找到并返回了上一个排列。这个方法对于理解和操作有序数据集具有重要意义。
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