113题 Remove Duplicates from Sorted List II

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本文介绍了一种算法，用于从已排序的链表中移除所有重复出现的节点，只保留原始链表中独一无二的数值。通过实现一个解决方案类的方法 `deleteDuplicates`，该方法接收链表的头节点作为参数，并返回去除重复项后的链表。

Remove Duplicates from Sorted List II

Description
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

/**
 * Definition for ListNode
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) {
 *         val = x;
 *         next = null;
 *     }
 * }
 */

public class Solution {
    /**
     * @param head: head is the head of the linked list
     * @return: head of the linked list
     */
    public ListNode deleteDuplicates(ListNode head) {
        // write your code here
        if(head == null|| head.next == null){
            return head ;
        }
        ListNode dummy = new ListNode(0) ;
        dummy.next = head ;
        head = dummy ;
        while(head.next != null && head.next.next != null){
            if(head.next.val == head.next.next.val){
                int val = head.next.val ;
                //tail.next = head.next.next ;
                while(head.next != null && head.next.val == val){
                    head.next = head.next.next ;
                }
            }else{
                head = head.next ;
                //tail.next = head;
            }
        }
        return dummy.next ;

    }
}