1064. Complete Binary Search Tree

本文介绍如何通过给定的一组非负整数构造一个既是二叉搜索树又是完全二叉树的数据结构,并实现了该树的层次遍历输出。文章详细解释了构建过程及其背后的原理。

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A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

  • The left subtree of a node contains only nodes with keys less than the node's key.
  • The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
  • Both the left and right subtrees must also be binary search trees.

A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.

Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<=1000). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.

Output Specification:

For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

Sample Input:
10
1 2 3 4 5 6 7 8 9 0
Sample Output:
6 3 8 1 5 7 9 0 2 4

#include <iostream>
#include <vector>
#include "stdio.h"
#include <algorithm>

using namespace std;

vector<int> tree;
vector<int> nodes;
int N;
void buildTree(int root)
{
	static int index = 1;
	if(root >N) return;
	buildTree(root *2);
	tree[root] = nodes[index++];
	buildTree(root*2 +1);
}
int main()
{
	cin >> N;
	nodes.resize(N+1);
	tree.resize(N+1);
	for (int i =1;i<=N;i++)
	{
		scanf("%d",&nodes[i]);
	}
	sort(nodes.begin(),nodes.end());
	buildTree(1);
	printf("%d",tree[1]);
	printf(" ");
	for (int i=2;i<N;i++)
	{	
		printf("%d",tree[i]);
		printf(" ");
	}
	printf("%d",tree[N]);
	cout<<endl;
	return 0;
}



没有AC,有一个测试点错误。


/************************************************************************/
/* 完全二叉树的结点i如果从1开始编号,那么左儿子为2*i,右儿子为2*i+1;
而二叉搜索树的中序遍历为升序,因此只需要对输入序列按照升序排序,
然后对完全二叉树进行中序遍历,填入相应的元素即可。
/************************************************************************/
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