写一个bat文件，删除文件名符合特定规则，且更改日期在某个日期之前的所有目录

Tom罗

于 2015-01-17 11:37:35 发布

阅读量509

点赞数

CC 4.0 BY-SA版权

分类专栏： ORACLE

本文链接：https://blog.youkuaiyun.com/cadnhuiyuannumber1/article/details/42804143

ORACLE 专栏收录该内容

4 篇文章

订阅专栏

本文介绍了一个批处理脚本，该脚本能够选择性地删除E:deployment路径下，创建日期早于指定日期且文件名符合特定规则的所有目录。通过用户输入日期参数，脚本将列出符合条件的目录供确认，并在用户同意后执行删除操作。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

问题描述：

写一个bat文件，删除文件名符合特定规则，且更改日期在某个日期之前的所有目录

@echo off
echo The program will select the E:\deployment\ as default working path.
setlocal enabledelayedexpansion

::WORKING DIRECTORY
set workPath=E:\deployment\

echo The directory created before the date will be deleted,
set /p deleteDate=please input the date.(yyyy/MM/dd or yyyy-MM-dd):

set delete_date=%deleteDate:~0,4%%deleteDate:~5,2%%deleteDate:~8,2%

echo These directory have been selected
for /D /R %workPath% %%i in (*_T*) do (
  set file_date=%%~ti
  set file_date=!file_date:~6,4!!file_date:~0,2!!file_date:~3,2!
 
  if !file_date! lss %delete_date%  (
      echo       %%i    %%~ti
  )
)

echo.
echo.
set /p choice=Do you want to delete them?  (Y or N):
if /i "%choice%" EQU "Y" (
    for /D /R %workPath% %%i in (*_T*) do (
        set file_date=%%~ti
        set file_date=!file_date:~6,4!!file_date:~0,2!!file_date:~3,2!
        
        if !file_date! lss %delete_date%  (
           echo  deleting %%i    %%~ti
	       rd /S /Q %%i
        )
    )
    
    echo.
    echo Success,You have deleted the selected directory.
)

if /i "%choice%" EQU "N" (
    echo You cancel the progress.
)