Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______6______
/ \
___2__ ___8__
/ \ / \
0 4 7 9
/ \
3 5
For example, the lowest common ancestor (LCA) of nodes 2 and 8 is 6. Another example is LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.
思路就是找到一个节点的所有父节点,放在一个队列里面。然后两个节点的所有父节点形成的两个队列找到分叉(最后一个相同的节点),就是最近的一个父节点。
二叉搜索树中最低公共祖先的算法解析

本文探讨了如何在二叉搜索树(BST)中寻找两个给定节点的最低公共祖先(LCA)。按照LCA的定义,它是T树中同时拥有v和w作为子孙的最低节点。通过将节点的父节点存入队列,并比较两个节点的父节点队列找到分叉点,即为最近的公共父节点。文中提到了使用递归的方法来实现这一过程。
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