Given a binary tree, return the bottom-up level order traversal of its nodes’ values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its bottom-up level order traversal as:
[
[15,7],
[9,20],
[3]
]
想着用之前顺序的方法,但是List在add的时候用栈来存放,然后再pop出来就逆序了。
public List<List<Integer>> levelOrder1(TreeNode root) {