CHNMSCS

动态规划

Using the leetcode 198 to walk through how to use the DP framework to do this problem.1. A function or array that answers the problem for a given stateFirst, we need to decide on state variables. As a reminder, state variables should be fully capable of

When it comes to solving an algorithm problem, especially in a high-pressure scenario such as interview, half the battle is figuring out how to even approach the problem. In the first section, we define what makes a problem a good candidate for dynamic pro

There are two ways to implement a DP algorithm:Bottom-up, also known as tabulationTop-down, also known as memoizationBottom-up (Tabulation)Bottom-up is implemented with iteration and starts at the base cases. Using the Fibonacci sequence as an examp

Dynamic Programming (DP) is a programming paradigm that can systematically and efficiently explore all possible solutions to a problem. As such, it is capable of solving a wide variety of problems that often have the following characteristics:The problem

题目：代码：if __name__ == '__main__': x = int(input()) y = int(input()) z = int(input()) n = int(input()) res = [] for i in range(x+1): for j in range(y+1): for k in range(z+1): if i+j+k != n:

题目：代码：def is_leap(year): leap = False if year % 4 == 0: if year % 100 != 0: leap = True elif year % 400 == 0: leap = True return leap year = int(input())print(is_leap(year))谢谢各位捧

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the minimumDistances function below.def minimumDistances(a): dictionary = {} distance = 0 min_distance = len(a) for i in range(len(a)):

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the jumpingOnClouds function below.def jumpingOnClouds(c): index = 0 count = 0 while index < len(c): if index == len(c) - 1:

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the extraLongFactorials function below.def extraLongFactorials(n): if n <= 1: return 1 return n * extraLongFactorials(n-1) if __name__ ==

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the findDigits function below.def findDigits(n): count = 0 arr = [int(d) for d in str(n)] for i in range(len(arr)): if arr[i] == 0:

题目：代码：class Solution: def maxProfit(self, prices: List[int]) -> int: if not prices: return 0 profit = 0 buy_stock = prices[0] for i in range(len(prices)): if buy_stock > prices[i

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the viralAdvertising function below.def viralAdvertising(n): shared = 5 liked = 2 cumulative = 2 for i in range(n-1): shared = (shared /

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sysdef beautify(num, k): return abs(int(str(num)) - int(str(num)[::-1])) % k == 0# Complete the beautifulDays function below.def beautifulDays(i, j, k): cnt = 0

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the angryProfessor function below.def angryProfessor(k, a): onTime = 0 for i in range(len(a)): if a[i] <= 0: onTime += 1 if o

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the utopianTree function below.def utopianTree(n): if n == 0: return 1 H = 1 for i in range(n): if i % 2 == 0: H = H * 2

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the designerPdfViewer function below.def designerPdfViewer(h, word): change_to_num = [] for i in range(len(word)): change_to_num.append(ord(word

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the hurdleRace function below.def hurdleRace(k, height): maxHeight = max(height) if maxHeight - k >= 0: return maxHeight - k else:

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the catAndMouse function below.def catAndMouse(x, y, z): if abs(z-x) < abs(z-y): return 'Cat A' if abs(z-x) > abs(z-y): return ('

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys## Complete the 'countingValleys' function below.## The function is expected to return an INTEGER.# The function accepts following parameters:# 1. INTEGER steps# 2.

题目：代码：#!/bin/python3import osimport sys## Complete the getMoneySpent function below.#def getMoneySpent(keyboards, drives, b): # # Write your code here. # keyboards_sort = sorted(keyboards) drives_sort = sorted(drives) if

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the birthday function below.def birthday(s, d, m): count = 0 for i in range(len(s)): if sum(s[i:m+i]) == d: count += 1 return c

题目：代码：#!/bin/python3import osimport sys## Complete the pageCount function below.#def pageCount(n, p): # # Write your code here. # if (p <= n): return min(p//2, n//2 - p//2) if __name__ == '__main__': fptr

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the sockMerchant function below.def sockMerchant(n, ar): count = 0 ar.sort() ar.append('*') i = 0 while i<n: if ar[i]==ar[i+1]:

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the bonAppetit function below.def bonAppetit(bill, k, b): result = 0 for i in range(len(bill)): if i == k: continue result

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the dayOfProgrammer function below.def dayOfProgrammer(year): result = '' if year >= 1700 and year <=1917: if year % 4 == 0:

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the breakingRecords function below.def breakingRecords(scores): highest_score_count = 0 lowest_score_count = 0 highest = scores[0] lowest = scor

题目：代码：#!/bin/python3import mathimport osimport randomimport reimport sys# Complete the kangaroo function below.def kangaroo(x1, v1, x2, v2): if v2 - v1 == 0 and x1 != x2: return 'NO' if (x1-x2)%(v2-v1) == 0 and (x1-x2)*(v2-v1)

题目：python3代码：class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: nums = [(num, idx) for idx, num in enumerate(nums)] nums.sort(key=lambda x: x[0]) left, right = 0, len(nums) - 1 while left

题目：python3代码：简单版：class Solution: def myPow(self, x: float, n: int) -> float: return x ** n递归版：class Solution: def myPow(self, x: float, n: int) -> float: if n == 0: return 1 if n < 0:

题目：python3代码：# Definition for a binary tree node.# class TreeNode:# def __init__(self, val=0, left=None, right=None):# self.val = val# self.left = left# self.right = rightclass Solution: def postorderTraversal(self,

题目：python3 代码：# Definition for a binary tree node.# class TreeNode:# def __init__(self, val=0, left=None, right=None):# self.val = val# self.left = left# self.right = rightclass Solution: def hasPathSum(self, root:

题目：python3代码：# Definition for a binary tree node.# class TreeNode:# def __init__(self, val=0, left=None, right=None):# self.val = val# self.left = left# self.right = rightclass Solution: def isBalanced(self, root:

题目：python3代码：# Definition for a binary tree node.# class TreeNode:# def __init__(self, val=0, left=None, right=None):# self.val = val# self.left = left# self.right = rightclass Solution: def isSameTree(self, p: Tree

题目：python代码：class Solution: def plusOne(self, digits: List[int]) -> List[int]: i = len(digits)-1 digits[i] += 1 while digits[i]==10: digits[i] = 0 if i==0: digits.insert(0,1)

题目：python 代码：class Solution: def maxSubArray(self, nums: List[int]) -> int: if (len(nums) == 1): return nums[0] result = [] result.append(nums[0]) for i in range(1,len(nums)): result.append(

题目：用python3来写代码：class Solution: def searchInsert(self, nums: List[int], target: int) -> int: if len(nums) == 0: return 0 for i in range(len(nums)): if nums[i] < target and i == len(nums)-1: # The last o

题目：python3代码：class Solution: def strStr(self, haystack: str, needle: str) -> int: if (len(haystack) == 0 and len(needle) == 0) or (len(haystack) != 0 and len(needle) == 0): return 0 if len(haystack) < len(needle):

题目：python 代码：# Definition for singly-linked list.#class ListNode:# def __init__(self, val=0, next=None):# self.val = val# self.next = nextclass Solution: def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode:

题目：python code:class Solution: def isValid(self, s: str) -> bool: stack = [] for i in range(len(s)): character = s[i] if character != '(' and character != "{" and character != '[' and character != ")" and