题目描述
输入一棵二叉树,判断该二叉树是否是平衡二叉树。
题解
#include <iostream>
#include <algorithm>
#include <cmath>
using namespace std;
struct TreeNode
{
int val;
struct TreeNode *left;
struct TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
TreeNode() {}
};
TreeNode* newTree()
{
TreeNode* node = new TreeNode;
int x;
cin >> x;
if (!x)node = NULL;
else
{
node->val = x;
node->left = newTree();
node->right = newTree();
}
return node;
}
int getDepth(TreeNode* root)
{
if (!root)return 0;
int left = getDepth(root->left);
if (left == -1)return -1;
int right = getDepth(root->right);
if (right == -1)return -1;
return abs(left - right) > 1 ? -1 : 1 + max(left, right);
}
bool IsBalanced_Solution(TreeNode* pRoot)
{
return getDepth(pRoot) != -1;
}
int main()
{
ios::sync_with_stdio(false);
TreeNode* root = NULL;
root = newTree();
cout << IsBalanced_Solution(root) << endl;
return 0;
}