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最新推荐文章于 2022-02-25 19:38:17 发布

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#include #c

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本文介绍了一种使用C++实现的算法，该算法能够将输入的整数转换为由字符组成的特定数字图案。通过定义行数和列数，利用循环结构绘制每个数字的轮廓，适用于数字显示或艺术创作。

#include <iostream>
#define MAX_R 30
#define MAX_C 120
using namespace std;

char res[MAX_R][MAX_C];
int dNum, num;
int digit[10];
int r, c, wide;

void init()
{
   //dNum = 0;
   for(int i = 1; i <= r; i++)
       for(int j = 1; j <= c; j++)
           res[i][j] = ' ';
}

void getDigit(int temp)
{
   if(temp <= 10)
       digit[++dNum] = temp;
   else
   {
       getDigit(temp / 10);
       digit[++dNum] = temp % 10;
   }
}

void fill()
{
   int seq, curDigit, startC, endC, midR, tr, tc;
   for(seq = 1; seq <= dNum; seq++)
   {
       curDigit = digit[seq];
       startC = (seq - 1) * (wide + 3) + 1;
       endC = seq * (wide + 3) - 1;
       midR = 2 + wide;

       for(tr = 1; tr <= r; tr++)
       {
           for(tc = startC; tc <= endC; tc++)
           {
               if(tr == 1 && tc > startC && tc < endC)
               {
                   if(curDigit != 1 && curDigit != 4)
                       res[tr][tc] = '-';
               }
               else if(tc == startC && tr > 1 && tr < midR)
               {
                   if(curDigit != 1 && curDigit != 2 && curDigit != 3 && curDigit != 7)
                       res[tr][tc] = '|';
               }
               else if(tc == endC && tr > 1 && tr < midR)
               {
                   if(curDigit != 5 && curDigit != 6)
                       res[tr][tc] = '|';
               }
               else if(tr == midR && tc > startC && tc < endC)
               {
                   if(curDigit != 1 && curDigit != 7 && curDigit != 0)
                       res[tr][tc] = '-';
               }
               else if(tc == startC && tr > midR && tr < r)
               {
                   if(curDigit == 2 || curDigit == 6 || curDigit == 8 || curDigit == 0)
                       res[tr][tc] = '|';
               }
               else if(tc == endC && tr > midR && tr < r)
               {
                   if(curDigit != 2)
                       res[tr][tc] = '|';
               }
               else if(tr == r && tc > startC && tc < endC)
               {
                   if(curDigit != 1 && curDigit != 4 && curDigit != 7)
                       res[tr][tc] = '-';
               }
           }
       }
   }
}
int main()
{
   while(cin>>wide>>num && !(wide == 0 && num == 0))
   {
       dNum = 0;
       getDigit(num);
       r = 2 * wide + 3;
       c = dNum * (wide + 3) - 1;
       init();
       fill();
       for(int tr = 1; tr <= r; tr++)
       {
           for(int tc = 1; tc <= c; tc++)
               cout<<res[tr][tc];
           cout<<endl;
       }
       cout<<endl;
   }
   return 0;
}