import re, itertools
def fromroman(RomanChar):
Pattern = "^(M{0,3})(CM|CD|D?C{0,3})(XC|XL|L?X{0,3})(IX|IV|V?I{0,3})$"
CharList = list(re.search(Pattern, RomanChar).groups())
return int(reduce(lambda X,Y: X + Y,
map(mapNum, itertools.izip(CharList, [1000, 100, 10, 1]))))
def cmpfun(x, y):
StrSeq = "IVXLCDM"
if StrSeq.index(x) < StrSeq.index(y):
return 1
elif StrSeq.index(x) > StrSeq.index(y):
return -1
return 0
def mapNum((StrNum, Level)):
if StrNum == "":
return "0"
Dict = {1 :{'I':1, 'V':5, 'X':10},
10 :{'X':1, 'L':5, 'C':10},
100 :{'C':1, 'D':5, 'M':10},
1000:{'M':1}}
CharDict = Dict[Level]
MaxChr = sorted(StrNum, cmpfun)[0]
AddList = map(lambda x: CharDict[x], list(StrNum[StrNum.index(MaxChr):]))
DelList = map(lambda x: CharDict[x], list(StrNum[:StrNum.index(MaxChr)]))
return str(sum(AddList) - sum(DelList))
本文介绍了一个将罗马数字转换为阿拉伯数字的Python实现方法。通过正则表达式验证输入的合法性,并利用lambda表达式和映射函数进行数值计算。此外,还提供了一种比较字符大小的方法以辅助计算。
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