冰淇淋色的天空

[['abc',6],['bcd',3],['bcd',2]]->[['abc',6],['bcd',5]]list1 = [['abc',6],['bcd',3],['bcd',2]]dic = {}for item in list1: if item[0] not in dic: dic[item[0]] = item[1] else: dic[item[0]] += item[1]list_new = [[x,y] for x,y in.

def sum_of_diagonals(two_d_list): """[[1,3,2,4],[8,7,5,6],[15,13,12,11],[9,-8,-10,-6]]""" main_diag = [] vice_diag = [] for i in range(len(two_d_list)): for j in range(len(two_d_list)): if j == i: main...

def row_and_col_squared_value(two_d_list): """[[1,2,3],[4,5,6],[7,8,9]]""" row_squared = [] col_squared = [] extend_squared = [] row_len = 0 for row in two_d_list: row_len = len(row) tmp = list(map(lambda x: pow(x...

re.match函数re.match 尝试从字符串的起始位置匹配一个模式，如果不是起始位置匹配成功的话，match()就返回noneprint(re.match('www', 'www.runoob.com').span()(0, 3)print(re.match('com', 'www.runoob.com')) # 不在起始位置匹配Noneline = "Cats ar...

文末有参考答案1、将元组 (1,2,3) 和集合 {4,5,6} 合并成一个列表。2、在列表 [1,2,3,4,5,6] 首尾分别添加整型元素 7 和 0。3、反转列表 [0,1,2,3,4,5,6,7] 。4、反转列表 [0,1,2,3,4,5,6,7] 后给出中元素 5 的索引号。5、分别统计列表 [True,False,0,1,2] 中 True,False,0,1,2的...

a=[[1], ['a','b'], [2.3, 4.5, 6.7]]1.用列表推导式[col for row in a for col in row ]2.用嵌套循环展开b=[]for row in a: for col in row: b.append(col)3.用sum对列表的求和sum(a,[])4.导入相关的包from iter...