本文为《Thomas’ Calculus Early Transcendentals》阅读笔记
- Definition: A function fff from a set DDD to a set YYY is a rule that assigns a unique(single) element f(x)∈Yf(x) \in Yf(x)∈Y to each elements x∈Dx \in Dx∈D
- The set DDD of all possible input values is called the domain of the function.
- The set of all output values of f(x)f(x)f(x) as xxx varies throughout DDD is called the range of the function
- If fff is a function with domain DDD, its graph consists of the points in the Cartesian plane whose coordinates are the input-output pairs for fff.
- Another way to represented function is numerically, through a table of values. The graph consisting of only the points in the table is called a scatterplot.
- Not every curve of coordinate plane can be the graph of a function. A function fff can have only one value f(x)f(x)f(x) for each xxx in the domain, so no vertical line can intersect the graph of a function more than once. If aaa is in the domain of function fff, then the vertical line x=ax = ax=a will intersect the graph of fff at the single point (a,f(a))(a, f(a))(a,f(a))
- Sometimes a function is described in pieces by using different formulas on different parts of its domain. One example is the absolute value function:
∣x∣={x,x≥0−x,x<0 |x| = \begin{dcases} x,&x \ge 0\\ -x,&x < 0 \end{dcases} ∣x∣={x,−x,x≥0x<0 - Definition: Let fff be a function defined on an interval III and let x1x_{1}x1 and x2x_{2}x2 be any points in III.
1) If f(x2)>f(x1)f(x_{2}) > f(x_{1})f(x2)>f(x1) whenever x1<x2x_{1} < x_{2}x1<x2, then fff is said to be increasing on III
2) If f(x2)<f(x1)f(x_{2}) < f(x_{1})f(x2)<f(x1) whenever x1<x2x_{1} < x_{2}x1<x2, then fff is said to be decreasing on III - Definition: A function y=f(x)y = f(x)y=f(x) is an
even function of x if f(−x)=f(x)f(-x) = f(x)f(−x)=f(x)
odd function of x if f(−x)=−f(x)f(-x) = -f(x)f(−x)=−f(x)
for every xxx in the function’s domain.
The graph of an even function is symmetric about the y-axis.
The graph of an odd function is symmetric about the origin. - A function of the form f(x)=mx+bf(x) = mx + bf(x)=mx+b, for constants mmm and bbb, is called a linear function.
- A function f(x)=xaf(x) = x^af(x)=xa, where aaa is a constant, is called a power function.
- A function ppp is a polynomial if
p(x)=anxn+an−1xn−1+…+a1x+a0 p(x) = a_{n} x^n + a_{n-1} x^{n-1} + \ldots + a_{1}x + a_{0} p(x)=anxn+an−1xn−1+…+a1x+a0
where nnn is a nonnegative integer and the numbers a0,a1,a2,…,ana_{0}, a_{1}, a_{2}, \ldots, a_{n}a0,a1,a2,…,an are real constants(called the coefficients of the polynomial). - A rational function is a quotient or ratio f(x)=p(x)/q(x)f(x) = p(x)/q(x)f(x)=p(x)/q(x), where ppp and qqq are polynomials. The domain of a rational function is the set of all real xxx for which q(x)≠0q(x) \neq 0q(x)̸=0.
- Any function constructed from polynomials using algebraic operations (addition, subtraction, division, multiplication, and taking roots) lies within the class of algebraic functions.
- The six basic trigonometric functions are reviewed in Section 1.3.
- Functions of the form f(x)=axf(x) = a^{x}f(x)=ax, where the base a>0a > 0a>0 is a positive constant and a≠1a \neq 1a̸=1, are called exponential function.
- Logarithmic functions are the functions f(x)=logaxf(x) = \log_{a}xf(x)=logax, where the base a≠1a \neq 1a̸=1 is a positive constant.
Exercises
In exercises 1-6, find the domain and range of each function.
- f(x)=1+x2f(x) = 1 + x^2f(x)=1+x2 domain: x∈(−∞,+∞)x \in (-\infty, +\infty)x∈(−∞,+∞) range: f(x)∈[1,+∞)f(x) \in [1, +\infty)f(x)∈[1,+∞)
- f(x)=1−xf(x) = 1 - \sqrt{x}f(x)=1−x domain: x∈[0,+∞)x \in [0, +\infty)x∈[0,+∞) range: f(x)∈(−∞,1]f(x) \in (-\infty, 1]f(x)∈(−∞,1]
- F(x)=5x+10F(x) = \sqrt{5x + 10}F(x)=5x+10 domain: x∈[−2,+∞)x \in [-2, +\infty)x∈[−2,+∞) range: F(x)∈[0,+∞)F(x) \in [0, +\infty)F(x)∈[0,+∞)
- g(x)=x2−3xg(x) = \sqrt{x^2 - 3x}g(x)=x2−3x domain: x∈(−∞,0]⋃[3,+∞)x \in (-\infty, 0] \bigcup [3, +\infty)x∈(−∞,0]⋃[3,+∞) range: g(x)∈[0,+∞)g(x) \in [0, +\infty)g(x)∈[0,+∞)
- f(t)=43−tf(t) = \frac{4}{3-t}f(t)=3−t4 domain: t∈(−∞,3)⋃(3,+∞)t \in (-\infty,3) \bigcup (3, +\infty)t∈(−∞,3)⋃(3,+∞) range: f(t)∈(−∞,+∞)f(t) \in (-\infty, +\infty)f(t)∈(−∞,+∞)
- G(t)=2t2−16G(t) = \frac{2}{t^2 -16}G(t)=t2−162 domain: t∈(−∞,4)⋃(4,+∞)t \in (-\infty,4) \bigcup (4, +\infty)t∈(−∞,4)⋃(4,+∞) range: G(t)∈(−∞,−18]⋃(0,+∞)G(t) \in (-\infty, -\frac{1}{8}] \bigcup (0, +\infty)G(t)∈(−∞,−81]⋃(0,+∞)