数据结构结构不同，分配的大小不一定一样

#include <stdio.h>
struct fir
{
    char a;
    int b;
    char c
}fir;
struct tw
{
    char ab;
    char bb;
    int  cb
}tw;

int main(void)
{
int dd;
int cc;
dd=sizeof(fir);
cc=sizeof(tw);
printf("%d/n",dd);
printf("%d/n",cc);
}

-bash-3.00$ gcc -o two two.c
two.c:7: warning: no semicolon at end of struct or union
two.c:13: warning: no semicolon at end of struct or union
-bash-3.00$ ./two
12
8