#include <stdio.h>
#include <stdlib.h>
int main()
{
int a;
float b,sum=0;
for (a = 1; a <= 100; a++) {
b = 1.0 / a;
if (a % 2 == 0)
sum = sum + b;
else
sum = sum - b;
}
printf("%f\n",sum);
return 0;
}
计算1/1-1/2+1/3-1/4+1/5 …… + 1/99 - 1/100 的值,打印出结果
于 2023-10-14 18:22:17 首次发布