Java算法练习20200324（杭电1094 1093 1091）

依据大佬建议的 刷题步骤（杭电oj题目）

题目01

linkOJ
@description
Your task is to calculate the sum of some integers.
*
*

• Input
• Input contains multiple test cases, and one case one line.
• Each case starts with an integer N, and then N integers follow in the same line.
• Output
• For each test case you should output the sum of N integers in one line,
• and with one line of output for each line in input.
• Sample Input
• 4 1 2 3 4
• 5 1 2 3 4 5
• Sample Output
• 10
• 15

编码中遇到的问题

这题意思和1096差不多。只不过少了个输入规定行数。
题目中注意这句Input contains multiple test cases, and one case one line.
意思是输入只有遇到EOF的时候才停止，不然就是输出一次后继续进行下一次输入。

测试结果

ojbk。

全代码

import java.util.Scanner;

public class Main {
   public static void main(String[] args) {
       Scanner scanner = new Scanner(System.in);
       short sum;
       while (scanner.hasNextShort()) {
           sum = 0;
           short counter = scanner.nextShort();
           for (int i = 0; i < counter; i++) {
               sum+=scanner.nextShort();
           }
           System.out.println(sum);
       }
   }
}

题目02

linkOJ

@description
*Your task is to calculate the sum of some integers.

• Input
• Input contains an integer N in the first line, and then N lines follow.
• Each line starts with a integer M, and then M integers follow in the same line.
• Output
• For each group of input integers you should output their sum in one line,
• and with one line of output for each line in input.
• Sample Input
• 2
• 4 1 2 3 4
• 5 1 2 3 4 5
• Sample Output
• 10
• 15

编码中遇到的问题

该题和1096唯一的不同就是输出换不换行。这题输出不换行。

测试结果

ojbk。

全代码

import java.util.Scanner;
public class Main {
   public static void main(String[] args) {
       Scanner scanner = new Scanner(System.in);
       short n = scanner.nextShort();
       short[] results = new short[n];
       for (int i = 0; i < n; i++) {
           short counter = scanner.nextShort();
           for (int j = 0; j < counter; j++) {
               results[i]+=scanner.nextShort();
           }
       }
       for (int i = 0; i < n; i++) {
           System.out.println(results[i]);
       }
   }
}

题目03

linkOJ

@description

• Your task is to Calculate a + b.
• Input
• Input contains multiple test cases. Each test case contains a pair of integers a and b,
• one pair of integers per line.
• A test case containing 0 0 terminates the input and this test case is not to be processed.
• Output
• For each pair of input integers a and b you should output the sum of a and b in one line,
• and with one line of output for each line in input.
• Sample Input
• 1 5
• 10 20
• 0 0
• Sample Output
• 6
• 30

编码中遇到的问题

这题好判断，以“0 0”输入为结束符。

测试结果

ojbk。

全代码

import java.util.Scanner;
public class Main {
   public static void main(String[] args) {
       Scanner sc = new Scanner(System.in);
       short[] results = new short[Short.MAX_VALUE];
       short i = 0;
       while (sc.hasNextShort()) {
           short a = sc.nextShort();
           short b = sc.nextShort();
           if(a==0 && b==0) {
               for (int j = 0; j < results.length; j++) {
                   if(results[j] == 0) {
                       break;
                   }
                   System.out.println(results[j]);
               }
               return;
           }
           results[i] = (short) (a+b);
           i++;
       }
   }
}