Leetcode: Tenth Line

本文介绍了如何使用sed、awk及tail等命令来提取文件中的指定行。通过三种不同的方法展示了如何仅获取文件的第10行内容,并讨论了当文件行数不足10行时的处理方式。

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Get idea from here


Question

How would you print just the 10th line of a file?

For example, assume that file.txt has the following content:

Line 1
Line 2
Line 3
Line 4
Line 5
Line 6
Line 7
Line 8
Line 9
Line 10
Your script should output the tenth line, which is:
Line 10
[show hint]

Hint:
1. If the file contains less than 10 lines, what should you output?
2. There’s at least three different solutions. Try to explore all possibilities.


Solution

Mistakes are made


  1. didn’t consider the situation that file contain less than 10 lines.

head -n 10 file.txt | tail -n 1
It is not right


Correct Solution

Solution 1 (sed)

sed -n '10p' file.txt

Solution 2(awk)

awk 'if(NR==10){print $0}' file.txt

Solution 3

tail -n+10 file.txt | head -n 1

tail -n

-n, –lines=K Output the last K lines, instead of the default of the last 10; alternatively, use “-n +K” to output lines starting with the Kth.

Keep in mind that -n+K, output lines starting with Kth


take-home message

awk, sed, tail can all solve this problem. These three commands are able to deal with txt editor.

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