Description:
Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Note:
无
Solution:
Analysis and Thinking:
题目要求实现strStr()函数的功能,找一个字符串中是否包含另一个字符串,并返回包含的位置,使用暴力求解即可
Steps:
1. 定义两个变量分别存储haystack以及needle的传长度
2. 遍历haystack,设置一记录器counter,每次从当前位置开始查到当前值加needle长度长的子串
3. 判断当前遍历的子串是否与needle相等,如果是,返回当前位置值
4. 遍历无果,返回-1
Codes:
class Solution {
public:
int strStr(string haystack, string needle) {
int i = -1;
int lengthNeed = needle.size();
int lengthHay = haystack.size();
while(++i <= lengthHay-lengthNeed)
{
string record = haystack.substr(i, lengthNeed);
if(record == needle) return i;
}
return -1;
}
};
Results: