How can selenium web driver get to know when the new window has opened and then resume its execution-优快云博客

本文解决使用Selenium WebDriver自动化测试时，在点击按钮后快速打开新窗口导致的NoSuchWindowException问题。通过在操作之间引入等待或使用特定方法获取新窗口句柄，可以确保代码正确执行。

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http://stackoverflow.com/questions/9188343/how-can-selenium-web-driver-get-to-know-when-the-new-window-has-opened-and-then

3 down vote favorite

i am facing below issue in automating web application using selenium web driver.

Webpage has a button which when clicked opens new window.when i use the below code, it throws "OpenQA.Selenium.NoSuchWindowException: No window found"

WebDriver.FindElement(By.Id("id of the button that opens new window")).Click();
//Switch to new window
_WebDriver.SwitchTo().Window("new window name");
//Click on button present on the newly opened window
_WebDriver.FindElement(By.Id("id of button present on newly opened window")).Click();

To solve above issue i used wait between button click and switch statements

WebDriver.FindElement(By.Id("id of the button that opens new window")).Click();
Thread.Sleep(50000); //wait
//Switch to new window
_WebDriver.SwitchTo().Window("new window name");
//Click on button present on the newly opened window
_WebDriver.FindElement(By.Id("id of button present on newly opened window")).Click();

This solved the issue. But i do not want to use "Thread.Sleep(50000);" statement becauseif the window takes more time to open, code can fail and if window opens quickly then it makes the test slow unnecessarily. Is there any way to know when the window has opened and then the test can resume its execution???

asked Feb 8 at 5:37

Ozone
27 1 3

75% accept rate

feedback

2 Answers

active oldest votes

up vote 2 down vote accepted

You need to switch the control to pop-up window before doing any operations in it.

In this way you can solve your problem

before opening the popup window get the handle of main window and save it.

String mwh=driver.getWindowHandle();

Now try to open the popup window by performing some action:

driver.findElement(By.xpath("")).click();

Set s=driver.getWindowHandles();
//this method will you handle of all opened windows

Iterator ite=s.iterator();

while(ite.hasNext())
{
    String popupHandle=ite.next().toString();
    if(!popupHandle.contains(mwh))
    {
                driver.switchTo().window(popupHandle);
                /**/here you can perform operation in pop-up window**
                //After finished your operation in pop-up just select the main window again
                driver.switchTo().window(mwh);
    }
}

edited Feb 9 at 14:34

Jav_Rock
5,645 3 16 50

answered Feb 8 at 14:51

Santoshsarma
76 4

Thanks for the reply.It is working. – Ozone Feb 14 at 4:45

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up vote 0 down vote

You could wait until the operation succeeds e.g., in Python:

from selenium.common.exceptions    import NoSuchWindowException
from selenium.webdriver.support.ui import WebDriverWait

def found_window(name):
    def predicate(driver):
        try: driver.switch_to_window(name)
        except NoSuchWindowException:
             return False
        else:
             return True # found window
    return predicate

driver.find_element_by_id("id of the button that opens new window").click()        
WebDriverWait(driver, timeout=50).until(found_window("new window name"))
WebDriverWait(driver, timeout=10).until( # wait until the button is available
    lambda x: x.find_element_by_id("id of button present on newly opened window"))\
    .click()