Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1 / \ 2 5 / \ \ 3 4 6
The flattened tree should look like:
1 \ 2 \ 3 \ 4 \ 5 \ 6
所见即所得!!!
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void flatten(TreeNode *root) {
while(root != NULL) {
if(root->left != NULL) {
TreeNode *rightmost = root->left->right;
while(rightmost != NULL && rightmost->right != NULL) {
rightmost = rightmost->right;
}
TreeNode *rootright = root->right;
if(rightmost == NULL) {
rightmost = root->left;
}
root->right = root->left;
root->left = NULL;
rightmost->right = rootright;
}
root = root->right;
}
}
};