webplayer的截图实现

最新推荐文章于 2023-04-13 09:14:10 发布

Rains卍Soft

最新推荐文章于 2023-04-13 09:14:10 发布

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本文介绍了一个使用Unity实现屏幕截图并上传到服务器的方法。通过C#脚本捕获当前屏幕画面，将其转换为PNG格式，然后利用WWWForm上传至指定URL。服务器端采用PHP接收并保存图片。

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首先是建一个 C# 类：
using System;
using UnityEngine;
using System.Collections;
public class PostPng
{
public static string UploadUrl = http://127.0.0.1/getpng.php;
public static void UploadPNG(MonoBehaviour thread, string fileName, Action<bool> result)
{
thread.StartCoroutine(UploadPNG(fileName, result));
}
private static IEnumerator UploadPNG(string fileName, Action<bool> result)
{
yield return new WaitForEndOfFrame();
int width = Screen.width;
int height = Screen.height;
Texture2D tex = new Texture2D(width, height, TextureFormat.RGB24, false);
tex.ReadPixels(new Rect(0, 0, width, height), 0, 0);
tex.Apply();
byte[] bytes = tex.EncodeToPNG();
GameObject.Destroy(tex);
WWWForm form = new WWWForm();
form.AddField("enctype", "multipart/form-data");
form.AddBinaryData("PngUpload", bytes, fileName, "image/png");
WWW post = new WWW(UploadUrl , form);
yield return post;
if (string.IsNullOrEmpty(post.error) && result != null)
{
result(true);
}
else
{
result(false);
}
post.Dispose();
}
}
再建一个 Cube,再建一个 C# 脚本：
OnGUI()
{
if (GUI.Button(new Rect(440, Screen.height - 25, 65, 23), "Snapshot"))
{
LoadHelp.UploadPNG(this, "Snapshot", delegate(bool result)
{
if (result)
{
Application.ExternalEval("alert('ok')");
}
});
}
}
最后要建立一个接受图片上传的程序，用什么取决于你的web服务器，我这里用的是php：
<?php
$filename = "";
$field = "PngUpload";
$pngfolder = "snapshot/";
if ($_FILES[$field]["error"] > 0)
{
echo "Error: " . $_FILES[$field]["error"];
}
else
{
$filename = $pngfolder . $_FILES[$field]["name"] . ".png";
move_uploaded_file($_FILES[$field]["tmp_name"], $filename);
echo("ok");
}
?>