hdu 1002A + B Problem II（java）_a+b problem 2 csdnjava-优快云博客

本文详细解析了一个关于大数加法的问题，并提供了一种使用Java的BigInteger类进行大数运算的解决方案。通过实例演示了如何读取输入的大数、进行加法运算，并输出加法结果。

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A + B Problem II

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 253489 Accepted Submission(s): 48872

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

大数可用：

java.math.BigInteger

import java.util.*;
import java.math.*;

public class Main
{
	public static void main(String args[])
	{
		 Scanner cin=new Scanner(System.in);
		 BigInteger a,b;
		 int t;
		 t=cin.nextInt();
		 for(int i=1;i<=t;i++)
		 {
			 a=cin.nextBigInteger();
			 b=cin.nextBigInteger();
			 BigInteger sum=a.add(b);
			 System.out.println("Case "+i+":");
			 System.out.println(a+" + "+b+" = "+sum);
			 if(i<t)
				 System.out.println();
			 
		 }
	}
}