问题原文https://leetcode-cn.com/problems/kth-largest-element-in-a-stream/description/
这道题的技巧是在队列里面维护k个元素。
class KthLargest {
int k;
PriorityQueue<Integer> queue;
public KthLargest(int k, int[] nums) {
this.k = k;
queue = new PriorityQueue<>();
if(nums.length <= k) {
for(int ele:nums) queue.add(ele);
}else {
for(int i = 0;i<k;i++) queue.add(nums[i]);
for(int i = k;i<nums.length;i++) {
if(queue.peek()<nums[i]) {
queue.poll();
queue.add(nums[i]);
}
}
}
}
public int add(int val) {
if(queue.size()<k) {
queue.offer(val);
}else if(queue.peek()<val) {
queue.poll();
queue.offer(val);
}
return queue.peek();
}
}