str2 ="2018-10-29"
c =re.sub(r"(\d{4})-(\d{2})-(\d{2})","\g<1>/\g<2>/\g<3>",str2)
print(c)
转载于:https://www.cnblogs.com/leigepython/p/9883767.html
日期格式转换技巧
str2 ="2018-10-29"
c =re.sub(r"(\d{4})-(\d{2})-(\d{2})","\g<1>/\g<2>/\g<3>",str2)
print(c)
转载于:https://www.cnblogs.com/leigepython/p/9883767.html
154
5031
1072
1003

被折叠的 条评论
为什么被折叠?