先有如下需求:每周以周五为周的开始,持续到下周四为止;要输出给定日期的年份,周数,开始时间,结束时间
输入示例:
2019-12-27
输出示例:
2020,1,2019-12-27,2020-01-022019-12-27输入示例:
2020-02-27
输出示例:
2020,9,2020-02-21,2020-02-27
select
year(
if(5 - if(dayofweek(str_to_date(${strDate}, '%Y-%m-%d')) = 1, 8,
dayofweek(str_to_date(${strDate}, '%Y-%m-%d'))) < 0,
date_format(date_add(subdate(${strDate},
if(date_format(${strDate}, '%w') = 0, 7, date_format(${strDate}, '%w')) -
1),
interval 5 - 1 + 6 day), '%Y-%m-%d'),
date_format(date_add(subdate(date_sub(${strDate}, interval 7 day),
if(date_format(date_sub(${strDate}, interval 7 day), '%w') = 0, 7,
date_format(date_sub(${strDate}, interval 7 day), '%w')) - 1),
interval 5 - 1 + 6 day), '%Y-%m-%d')
)
) as YEAR,
if(5 - if(dayofweek(date_add(date(${strDate}), interval 7 day)) = 1, 8,
dayofweek(date_add(date(${strDate}), interval 7 day))) < 0,
week(date_add(date(${strDate}), interval 7 day), 3),
week(date(${strDate}), 3)) as WEEKS,
if(5 - if(dayofweek(date(${strDate})) = 1, 8, dayofweek(date(${strDate}))) < 0,
date_format(date_add(subdate(${strDate},
if(date_format(${strDate}, '%w') = 0, 7, date_format(${strDate}, '%w')) - 1),
interval 5 - 1 day), '%Y-%m-%d'),
date_format(date_add(subdate(date_sub(${strDate}, interval 7 day),
if(date_format(date_sub(${strDate}, interval 7 day), '%w') = 0, 7,
date_format(date_sub(${strDate}, interval 7 day), '%w')) - 1), interval 5 - 1
day), '%Y-%m-%d')
) as START_DAY,
if(5 - if(dayofweek(str_to_date(${strDate}, '%Y-%m-%d')) = 1, 8,
dayofweek(str_to_date(${strDate}, '%Y-%m-%d'))) < 0,
date_format(date_add(subdate(${strDate},
if(date_format(${strDate}, '%w') = 0, 7, date_format(${strDate}, '%w')) - 1),
interval 5 - 1 + 6 day), '%Y-%m-%d'),
date_format(date_add(subdate(date_sub(${strDate}, interval 7 day),
if(date_format(date_sub(${strDate}, interval 7 day), '%w') = 0, 7,
date_format(date_sub(${strDate}, interval 7 day), '%w')) - 1),
interval 5 - 1 + 6 day), '%Y-%m-%d')
) as END_DAY;
如需有详细需求(例如:以周四为周起始可以将SQL中的数字5改为4)