1001. A+B Format (20)

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本文介绍了一个简单的编程问题，即计算两个整数a和b的和，并以标准的千分位格式输出结果。文章提供了完整的AC代码实现，展示了如何根据不同数值范围进行格式化输出。

1001. A+B Format (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

分析题意：计算sum=a+b的和，并以千分位的形式输出，先判断sum的正负数，如果是负数，先输出‘-’，对sum取绝对值，再判读sum的取值范围

AC解题代码：

#include<cstdio>
#include<stdio.h>
using namespace std;
int main()
{
        int a,b;
        while(scanf("%d%d",&a,&b)!=EOF)
        {
                int sum=a+b;
                if(sum<0)
                {
                        printf("-");
                        sum=-sum;
                }
                if(sum<1000)
                        printf("%d\n",sum);
                else if(sum<1000000)
                        printf("%d,%03d\n",sum/1000,sum%1000);
                else
                     printf("%d,%03d,%03d\n",sum/1000000,(sum%1000000)/1000,sum%1000);
        }
        return 0;
}