题干: 请完成一个函数,输入一个二叉树,该函数输出它的镜像。
题解: 递归交换左右节点,先暂存左节点,因为递归之后左节点就变了
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public TreeNode mirrorTree(TreeNode root) {
if(root==null){
return root;
}
TreeNode temp = root.left;
root.left = mirrorTree(root.right);
root.right = mirrorTree(temp);
return root;
}
}