zoj2481 Unique Ascending Array

Unique Ascending Array

Time Limit: 2000MS

Memory Limit: 65536KB

64bit IO Format: %lld & %llu

Submit Status

Description

Given an array of integers A[N], you are asked to decide the shortest array of integers B[M], such that the following two conditions hold.

• For all integers 0 <= i < N, there exists an integer 0 <= j < M, such that A[i] == B[j]
• For all integers 0 =< i < j < M, we have B[i] < B[j]

Notice that for each array A[] a unique array B[] exists.

Input

The input consists of several test cases. For each test case, an integer N (1 <= N <= 100) is given, followed by N integers A[0], A[1], ..., A[N - 1] in a line. A line containing only a zero indicates the end of input.

Output

For each test case in the input, output the array B in one line. There should be exactly one space between the numbers, and there should be no initial or trailing spaces.

Sample Input

8 1 2 3 4 5 6 7 8
8 8 7 6 5 4 3 2 1
8 1 3 2 3 1 2 3 1
0

Sample Output

1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8
1 2 3

Source

Zhejiang Provincial Programming Contest 2005

 

 

 

分析：

水题。对于输入的整型数组，从小到大排序后去重输出就可以。

ac代码：

#include <iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
int a[101];
int main()
{
    int n,i;
    while(scanf("%d",&n)&&n)
    {
        for(i=0;i<n;i++)
        scanf("%d",&a[i]);
        sort(a,a+n);
        printf("%d",a[0]);
        for(i=1;i<n;i++)
        {
            if(a[i]==a[i-1])
            continue;
            printf(" %d",a[i]);
        }
        printf("\n");
    }
    return 0;
}