485. Max Consecutive Ones
Given a binary array, find the maximum number of consecutive 1s in this array.
就是让你求一个二进制数组中字符1的最大长度.....
Example 1:
Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Note:
- The input array will only contain
0and1. - The length of input array is a positive integer and will not exceed 10,000
class Solution():
def findMaxConsecutiveOnes(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
s=''.join([str(i) for i in nums])
return max(map(len,s.split('0')))
def findMaxConsecutiveOnes1(self,nums):
count1 = 0;
result= 0
for i in nums:
if i==1:
count1+=1
result=max(count1,result)
elif i==0:
count1=0
return result
s=Solution()
print s.findMaxConsecutiveOnes1([1,1,1,0,1])

本文介绍了一种高效算法,用于寻找给定二进制数组中最长连续1子串的长度。通过两种方法实现:一种利用字符串操作快速找到最长连续1的序列;另一种采用计数方式遍历数组,直接计算最长连续1的长度。
1119

被折叠的 条评论
为什么被折叠?



