one day one cannon
or
one week five cannons
412. Fizz Buzz
Write a program that outputs the string representation of numbers from 1 to n.
But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.
Example:
n = 15,
Return:
[
"1",
"2",
"Fizz",
"4",
"Buzz",
"Fizz",
"7",
"8",
"Fizz",
"Buzz",
"11",
"Fizz",
"13",
"14",
"FizzBuzz"
]
#coding=utf-8 class Solution(object): def fizzBuzz(self,n): result=[] for i in range(1,n+1): if i%3==0 and i%5==0: result.append("FizzBuzz") elif i%5==0: result.append("Buzz") elif i%3==0: result.append("Fizz") else: result.append(str(i)) return result def fizzBuzz1(self,n): return ['Fizz'*(not i % 3)+'Buzz'*(not i%5) or str(i) for i in range(1,n+1)] X=Solution() print X.fizzBuzz(20) print X.fizzBuzz1(20)
主要讲一下列表生成式。http://www.liaoxuefeng.com/wiki/001374738125095c955c1e6d8bb493182103fac9270762a000/00138681963899940a998c0ace64bb5ad45d1b56b103c48000
这句代码比较好,列表生成式, 字符串可以*bool值,也可以*整型数值return ['Fizz'*(not i % 3)+'Buzz'*(not i%5) or str(i) for i in range(1,n+1)]
>>> "abd"*0 '' >>> 6 6 >>> 'abd'*(not 6%3) 'abd' >>> not (1) False >>> not 1 False >>> 'abd'*True 'abd' >>>>>> 'abd'*6 'abdabdabdabdabdabd'

本文介绍了经典的编程面试题——FizzBuzz问题,并提供了两种不同的Python实现方案:一种使用传统循环结构,另一种则利用了列表生成式的简洁表达。通过示例代码展示了如何针对1到n的数字序列进行判断并返回特定字符串。
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