十六进制的double8字节 的string 转成double 保留两位小数

    public static String double_to_code(String data){
        char[] hexChars = data.toCharArray();
        int len = hexChars.length;
        byte[] bytes = new byte[len / 2];
        for (int i = 0; i < len; i += 2) {
            String hexPair = String.valueOf(hexChars[i])+String.valueOf(hexChars[i + 1]);
            bytes[i / 2] = (byte) Integer.parseInt(hexPair, 16);
        }
        long longValue = 0;
        for (byte b : bytes) {
            longValue <<= 8;
            longValue |= b & 0xFF; // 右移并按位或
        }

        // 或者使用 BigInteger
        BigInteger bi = new BigInteger(1, bytes);
        longValue = bi.longValue();
        double doubleValue = Double.longBitsToDouble(longValue);
        String strValue = String.format("%.2f", doubleValue); // 保留两位小数
        return  strValue;
    }