027:简单的SumArray
#include <iostream>
#include <string>
using namespace std;
template <class T>
T SumArray(T *a, T *b){
T sum=*a;
for (int i = 1; i < b-a; ++i) {
sum+=*(a+i);
}
return sum;
}
int main() {
string array[4] = { "Tom","Jack","Mary","John"};
cout << SumArray(array,array+4) << endl;
int a[4] = { 1, 2, 3, 4}; //提示:1+2+3+4 = 10
cout << SumArray(a,a+4) << endl;
return 0;
}
//TomJackMaryJohn
//10
028:简单的foreach
#include <iostream>
#include <string>
using namespace std;
template <class T, class pred>
void MyForeach(T *a, T *b, pred op){
for(;a!=b;a++){
op(*a);
}
}
void Print(string s)
{
cout << s;
}
void Inc(int & n)
{
++ n;
}
string array[100];
int a[100];
int main() {
int m,n;
while(cin >> m >> n) {
for(int i = 0;i < m; ++i)
cin >> array[i];
for(int j = 0; j < n; ++j)
cin >> a[j];
MyForeach(array,array+m,Print);
cout << endl;
MyForeach(a,a+n,Inc);
for(int i = 0;i < n; ++i)
cout << a[i] << ",";
cout << endl;
}
return 0;
}
// input:
//3 4
//Tom Mike Jack
//1 2 3 4
//1 2
//Peking
//100 200
// output:
//TomMikeJack
//2,3,4,5,
//Peking
//101,201,
029:简单的Filter
#include <iostream>
#include <string>
using namespace std;
template <class T, class oper>
T *Filter(T *a, T *b, T *c, oper op)
{
for (; a!=b;a++) {
if(op(*a)){
*c=*a;
c++;
}
}
return c;
};
bool LargerThan2(int n)
{
return n > 2;
}
bool LongerThan3(string s)
{
return s.length() > 3;
}
string as1[5] = {"Tom","Mike","Jack","Ted","Lucy"};
string as2[5];
int a1[5] = { 1,2,3,4,5};
int a2[5];
int main() {
string * p = Filter(as1,as1+5,as2,LongerThan3);//这里接收的是一个地址
for(int i = 0;i < p - as2; ++i)
cout << as2[i];
cout << endl;
int * p2 = Filter(a1,a1+5,a2,LargerThan2);
for(int i = 0;i < p2-a2; ++i)
cout << a2[i] << ",";
return 0;
}
030:你真的搞清楚为啥 while(cin >> n) 能成立了吗?
#include <iostream>
using namespace std;
class MyCin
{
private:
bool state= true;
public:
MyCin &operator >> (int &x){
int t;
cin>>t;
x = t;
if(x==-1) {
state=false;
}
return *this;
}
operator bool(){
// 类型转换构造函数,可以将对象转换为一个指定类型的数据
return state;
}
};
int main()
{
MyCin m;
int n1,n2;
while( m >> n1 >> n2)
cout << n1 << " " << n2 << endl;
return 0;
}
031:山寨版istream_iterator
#include <iostream>
#include <string>
using namespace std;
template <class T>
class CMyistream_iterator
{
private:
T t;
istream &s;
public:
CMyistream_iterator(istream &is):s(is){
s>>t;
};
T operator *(){
//重载*运算符
return t;
};
void operator ++(int){
//后置++要加一个参数表示
s>>t;
}
};
int main()
{
int t;
cin >> t;
while( t -- ) {
CMyistream_iterator<int> inputInt(cin);
int n1,n2,n3;
n1 = * inputInt; //读入 n1
int tmp = * inputInt;
cout << tmp << endl;
inputInt ++;
n2 = * inputInt; //读入 n2
inputInt ++;
n3 = * inputInt; //读入 n3
cout<<"there"<<endl;
cout << n1 << " " << n2<< " " << n3 << " ";
CMyistream_iterator<string> inputStr(cin);
string s1,s2;
s1 = * inputStr;
inputStr ++;
s2 = * inputStr;
cout << s1 << " " << s2 << endl;
}
return 0;
}
032:这个模板并不难
#include <iostream>
#include <string>
#include <cstring>
using namespace std;
template <class T>
class myclass {
private:
size_t size;
T *p;
public:
myclass(T *a, size_t _size){
size = _size;
p = new T[size];//析够函数用delete因此,这里要用new初始化数组
for (int i = 0; i < size; ++i) {
*(p+i) = a[i];
}
}
~myclass( ) {
delete [] p;
}
void Show()
{
for( int i = 0;i < size;i ++ ) {
cout << p[i] << ",";
}
cout << endl;
}
};
int a[100];
int main() {
char line[100];
while( cin >> line ) {
myclass<char> obj(line,strlen(line));;
obj.Show();
int n;
cin >> n;
for(int i = 0;i < n; ++i)
cin >> a[i];
myclass<int> obj2(a,n);
obj2.Show();
}
return 0;
}
033:排序,又见排序!
#include <iostream>
using namespace std;
bool Greater2(int n1,int n2)
{
return n1 > n2;
}
bool Greater1(int n1,int n2)
{
return n1 < n2;
}
bool Greater3(double d1,double d2)
{
return d1 < d2;
}
template <class T1,class T2>
void mysort(T1* t1, T1* t2, T2 op){
//这里写个排序
for (int i = 0; i < t2-t1; ++i) {
for (int j = i+1; j < t2-t1; ++j) {
if(op(*(t1+j), *(t1+i))){
T1 temp = *(t1+i);
*(t1+i)=*(t1+j);
*(t1+j)=temp;
}
}
}
};
#define NUM 5
int main()
{
int an[NUM] = { 8,123,11,10,4 };
mysort(an,an+NUM,Greater1); //从小到大排序
for( int i = 0;i < NUM; i ++ )
cout << an[i] << ",";
mysort(an,an+NUM,Greater2); //从大到小排序
cout << endl;
for( int i = 0;i < NUM; i ++ )
cout << an[i] << ",";
cout << endl;
double d[6] = { 1.4,1.8,3.2,1.2,3.1,2.1};
mysort(d+1,d+5,Greater3); //将数组从下标1到下标4从小到大排序
for( int i = 0;i < 6; i ++ )
cout << d[i] << ",";
return 0;
}