UVA10474 where is the Marble? STL初步

最新推荐文章于 2022-01-18 15:51:31 发布

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本文详细介绍了如何在C++中利用lower_bound函数从数组中查找特定值，并输出该值在数组中的位置。通过实例演示了数组排序和lower_bound函数的应用，适合C++初学者和中级开发者。

#include<iostream>
#include<algorithm>
using namespace std;
const int maxn = 10000;

int main()
{
    int n, q, x, a[maxn], kase = 0;
    while(cin >> n >> q && n){
         cout << "CASE# " << ++kase << ":" << endl;
         for(int i = 0; i < n; i++) cin >> a[i];
         sort(a, a+n);
         while(q--){
            cin >> x;
            int p = lower_bound(a, a+n, x) - a;
            if(a[p] == x) cout << x << " found at " << p+1 << endl;
            else cout << x << " not found\n";
         }
    }
    return 0;
}

lower_bound从数组中寻找x，返回找到的指针

#include<cstdio>
#include<algorithm>
using namespace std;
const int maxn = 10000;
int main()
{
    int n, q, kase = 0, x, a[maxn];
    while(scanf("%d%d",&n,&q) == 2 && n){
        printf("CASE# %d:\n",++kase);
        for(int i = 0; i < n; i++) scanf("%d",&a[i]);
        sort(a, a+n);
        for(int i = 0; i < q; i++){
            scanf("%d", &x);
            int p = lower_bound(a, a+n, x) - a;
            if(a[p] == x) printf("%d found at %d\n",x,p+1);
            else printf("%d not found\n",x);
        }
    }
    return 0;
}