Leecode刷题：整数反转

题目连接：https://leetcode-cn.com/problems/reverse-integer/

实现秀了波编译器，代码如下

class Solution {
public:
    int reverse(int x) {
        int p = 0;
		int nMax = int(pow(2, 31) - 1);
		while (x)
		{
			if ((double)nMax / fabs(p) < 10)
			{
				return 0;
			}
			p *= 10;
			p += x % 10;
			x /= 10;
		}
		return p;
    }
};

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