如果当前节点的值与下一节点相同,则删除下一节点,否则当前节点后移一位。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
ListNode* cur=head;
while(cur&&cur->next){
if(cur->val==cur->next->val){
//ListNode* del=cur->next;
cur->next=cur->next->next;
//delete(del);
}
else{
cur=cur->next;
}
}
return head;
}
};