面向对象程序设计-实验十

题目1、

6-1 时间相加

（给出题目描述）

代码清单：

#include <iostream>

using namespace std;

class Time {

private:

 int hours,minutes, seconds;

public:

 Time(int h=0, int m=0, int s=0);

 Time operator + (Time &);

 void DispTime();

};

Time::Time(int h, int m, int s)

{

this->hours = h;

this->minutes = m;

this->seconds = s;

}

Time Time::operator+(Time &t)

{

Time tm4;

int a = 0, b = 0;

tm4.seconds = (this->seconds + t.seconds)%60;

a = (this->seconds + t.seconds) / 60;

tm4.minutes = (this->minutes + t.minutes + a) % 60;

b= (this->minutes + t.minutes + a) / 60;

tm4.hours = this->hours + t.hours + b;

     return tm4;

}

void Time::DispTime()

{

cout << hours << "h:" << minutes << "m:" << seconds << "s"<<endl;

}

/* 请在这里填写答案 */

int main() {

 Time tm1(8,75,50),tm2(0,6,16), tm3;

 tm3=tm1+tm2;

 tm3.DispTime();

 return 0;

}

运行结果截图

题目2

（给出题目描述）

7-1 复数类的运算

代码清单：

…………………………..

………………………….

#include<iostream>

using namespace std;

class Complex

{

public:

    Complex(double r = 0, double i = 0) :real(r), imag(i) {    }

    Complex operator+(Complex &c) const;//重载双目运算符'+'

    Complex operator-=(Complex &c ); //重载双目运算符'-='

    friend Complex operator-(Complex& c,Complex &cc);//重载双目运算符'-'

    void Display() const;

private:

    double real;

    double imag;

};

Complex Complex::operator+(Complex& c)const

{

    Complex c4;

    c4.real = this->real + c.real;

    c4.imag = this->imag + c.imag;

    return c4;

}

Complex Complex::operator-=(Complex& c)

{

    this->real -= c.real;

    this->imag -= c.imag;

    return *this;

}

Complex operator-(Complex& c,Complex &cc)

{

    Complex c4;

    c4.real = c.real - cc.real;

    c4.imag = c.imag - cc.imag;

    return c4;

}

void Complex::Display() const

{

    cout << "(" << real << ", " << imag << ")" << endl;

}

int main()

{

    double r, m;

    cin >> r >> m;

    Complex c1(r, m);

    cin >> r >> m;

    Complex c2(r, m);

    Complex c3 = c1 + c2;

    c3.Display();

    c3 = c1 - c2;

    c3.Display();

     c3 -= c1;

    c3.Display();

    return 0;

}

运行结果截图

题目3

（给出题目描述）

7-2 日程安排（多重继承+重载）

代码清单：

…………………………..

………………………….

#include<iostream>

using namespace std;

class Date{

    protected:

    int year;

    int month;

    int day;

    public:

    Date(int a,int b,int c):year(a),month(b),day(c){};

};

class Time{

    protected:

    int hour;

    int minute;

    int second;

    public:

    Time(int a,int b,int c):hour(a),minute(b),second(c){};

};

class Schedule:public Date,public Time{

    private:

    int ID;

    public:

    Schedule(int a=0,int b=0,int c=0,int d=0,int e=0,int f=0,int g=0):ID(a),Date(b,c,d),Time(e,f,g){};

    bool operator <(const Schedule &s2){

        if(year<s2.year){

            return true;

        }else if(year>s2.year){

            return false;

        }else if(month<s2.month){

            return true;

        }else if(month>s2.month){

            return false;

        }else if(day<s2.day){

            return true;

        }else if(day>s2.day){

            return false;

        }else if(hour<s2.hour){

            return true;

        }else if(hour>s2.hour){

            return false;

        }else if(minute<s2.minute){

            return true;

        }else if(minute>s2.minute){

            return false;

        }else if(second<s2.second){

            return true;

        }else if(second>s2.second){

            return false;

        }else{

            return true;

        }

    };

    void display(){

        cout<<"The urgent schedule is No."<<ID<<": "<<year<<"/"<<month<<"/"<<day<<" "<<hour<<":"<<minute<<":"<<second;

    }

};

int main(){

    Schedule d1,d2;

    int a,b,c,d,e,f,g;

    char ch;

    cin>>a>>b>>ch>>c>>ch>>d>>e>>ch>>f>>ch>>g;

    d1=Schedule(a,b,c,d,e,f,g);

    cin>>a;

    while(a){

        cin>>b>>ch>>c>>ch>>d>>e>>ch>>f>>ch>>g;

        d2=Schedule(a,b,c,d,e,f,g);

        if(d2.operator<(d1)){

            d1=d2;

        }

        cin>>a;

    }

    d1.display();

    

    return 0;

}

运行结果截图