Map实现快速增补数组

首次接触Map，为了实现快速增补数组,的确比运用字符数组String [ ]进行循环比较方便的多，节省大量运行时间。

代码如下：

package com;
import java.util.HashMap;
import java.util.Map;
public class test01 {
public static void main(String args[]){
StringBuffer sb = new StringBuffer();
StringBuffer sb1 = new StringBuffer();
Map<String,String> mapA = new HashMap<String,String>();
Map<String,String> mapB = new HashMap<String,String>();

String str1 = new String("2014|2015|2016");
String str2 = new String("4|5|6");
String str3 = new String("2011|2012|2013|2014|2015|2016|2017|2018");
String str4 = new String("0|0|0|0|0|0|0|0");

String[] str1Split =str1.split("\\|");
String[] str2Split =str2.split("\\|");
String[] str3Split =str3.split("\\|");
String[] str4Split =str4.split("\\|");

for(int i = 0;i < str1Split.length;i++){
mapA.put(str1Split[i], str2Split[i]);
}
for(int j = 0;j < str3Split.length;j++){
mapB.put(str3Split[j], str4Split[j]);
sb.append(str3Split[j] + "|");
}
for(String me : mapA.keySet()){
mapB.put(me, mapA.get(me));
}
for(String hh : mapB.keySet()){
sb1.append(mapB.get(hh) + "|");
}
sb.deleteCharAt(sb.length()-1);
sb1.deleteCharAt(sb1.length()-1);
System.out.println(sb);
System.out.println(sb1);
}
}

运行结果如下：

2011|2012|2013|2014|2015|2016|2017|2018
0|0|0|4|5|6|0|0|