Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element.
For example,
Given [3,2,1,5,6,4]
and k = 2, return 5.
Note:
You may assume k is always valid, 1 ≤ k ≤ array's length.
Solution:
class Solution {
public:
int findKthLargest(vector<int>& nums, int k) {
vector<int> n = nums;
int temp;
for (int i = 1; i < n.size(); i++)
for (int j = n.size() - 1; j >= i; j--)
if (n[j] > n [j - 1]) {
temp = n[j];
n[j] = n[j - 1];
n[j - 1] = temp;
}
return n[k - 1];
}
};